11008031 has 2 divisors, whose sum is σ = 11008032. Its totient is φ = 11008030.

The previous prime is 11008013. The next prime is 11008037. The reversal of 11008031 is 13080011.

Together with previous prime (11008013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11008031 is a prime.

It is a super-2 number, since 2×11008031² = 242353492993922, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11007997 and 11008015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11008037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5504015 + 5504016.

It is an arithmetic number, because the mean of its divisors is an integer number (5504016).

Almost surely, 2^11008031 is an apocalyptic number.

11008031 is a deficient number, since it is larger than the sum of its proper divisors (1).

11008031 is an equidigital number, since it uses as much as digits as its factorization.

11008031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 14.

The square root of 11008031 is about 3317.8352882565. The cubic root of 11008031 is about 222.4521194788.

Adding to 11008031 its reverse (13080011), we get a palindrome (24088042).

The spelling of 11008031 in words is "eleven million, eight thousand, thirty-one".