1100999983 has 2 divisors, whose sum is σ = 1100999984. Its totient is φ = 1100999982.

The previous prime is 1100999981. The next prime is 1100999987. The reversal of 1100999983 is 3899990011.

It is a weak prime.

It is an emirp because it is prime and its reverse (3899990011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1100999983 - 2¹ = 1100999981 is a prime.

Together with 1100999981, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100999981) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550499991 + 550499992.

It is an arithmetic number, because the mean of its divisors is an integer number (550499992).

Almost surely, 2^1100999983 is an apocalyptic number.

1100999983 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100999983 is an equidigital number, since it uses as much as digits as its factorization.

1100999983 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 157464, while the sum is 49.

The square root of 1100999983 is about 33181.3197899059. The cubic root of 1100999983 is about 1032.5928275543.

The spelling of 1100999983 in words is "one billion, one hundred million, nine hundred ninety-nine thousand, nine hundred eighty-three".