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11010000001141 is a prime number
BaseRepresentation
bin1010000000110111011100…
…1000111001100001110101
31102222112201211102101000001
42200031313020321201311
52420341440000014031
635225531342151301
72214306030611521
oct240156710714165
942875654371001
1011010000001141
113565350a74869
12129998a882531
1361b314111bab
142a0c5b6d8d81
151415de567861
hexa0377239875

11010000001141 has 2 divisors, whose sum is σ = 11010000001142. Its totient is φ = 11010000001140.

The previous prime is 11010000001069. The next prime is 11010000001153. The reversal of 11010000001141 is 14110000001011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7490736560241 + 3519263440900 = 2736921^2 + 1875970^2 .

It is a cyclic number.

It is not a de Polignac number, because 11010000001141 - 229 = 11009463130229 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11010000001841) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505000000570 + 5505000000571.

It is an arithmetic number, because the mean of its divisors is an integer number (5505000000571).

Almost surely, 211010000001141 is an apocalyptic number.

It is an amenable number.

11010000001141 is a deficient number, since it is larger than the sum of its proper divisors (1).

11010000001141 is an equidigital number, since it uses as much as digits as its factorization.

11010000001141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4, while the sum is 10.

Adding to 11010000001141 its reverse (14110000001011), we get a palindrome (25120000002152).

The spelling of 11010000001141 in words is "eleven trillion, ten billion, one thousand, one hundred forty-one".