Base | Representation |
---|---|
bin | 1010000000111000001111… |
… | …0010011100110100100001 |
3 | 1102222120021121202012210221 |
4 | 2200032003302130310201 |
5 | 2420342403312021233 |
6 | 35230004402523041 |
7 | 2214314215500124 |
oct | 240160362346441 |
9 | 42876247665727 |
10 | 11010212220193 |
11 | 356544a84310a |
12 | 1299a29966481 |
13 | 61b349086ab4 |
14 | 2a0c7b97c3bb |
15 | 141602ed742d |
hex | a0383c9cd21 |
11010212220193 has 2 divisors, whose sum is σ = 11010212220194. Its totient is φ = 11010212220192.
The previous prime is 11010212220191. The next prime is 11010212220199. The reversal of 11010212220193 is 39102221201011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9931214812689 + 1078997407504 = 3151383^2 + 1038748^2 .
It is a cyclic number.
It is not a de Polignac number, because 11010212220193 - 21 = 11010212220191 is a prime.
Together with 11010212220191, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11010212220191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505106110096 + 5505106110097.
It is an arithmetic number, because the mean of its divisors is an integer number (5505106110097).
Almost surely, 211010212220193 is an apocalyptic number.
It is an amenable number.
11010212220193 is a deficient number, since it is larger than the sum of its proper divisors (1).
11010212220193 is an equidigital number, since it uses as much as digits as its factorization.
11010212220193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 25.
The spelling of 11010212220193 in words is "eleven trillion, ten billion, two hundred twelve million, two hundred twenty thousand, one hundred ninety-three".
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