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11010303150055 = 5111877106652813
BaseRepresentation
bin1010000000111000100100…
…1101010100011111100111
31102222120111221211221010121
42200032021031110133213
52420343100101300210
635230021411502411
72214316401414556
oct240161115243747
942876457757117
1011010303150055
1135654970aa060
121299a542b7a07
1361b361b73051
142a0c89a8bd9d
1514160ae996da
hexa03893547e7

11010303150055 has 16 divisors (see below), whose sum is σ = 14421166897824. Its totient is φ = 8003227012480.

The previous prime is 11010303150001. The next prime is 11010303150073. The reversal of 11010303150055 is 55005130301011.

It is a happy number.

It is not a de Polignac number, because 11010303150055 - 211 = 11010303148007 is a prime.

It is a super-2 number, since 2×110103031500552 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 53223172 + ... + 53429641.

It is an arithmetic number, because the mean of its divisors is an integer number (901322931114).

Almost surely, 211010303150055 is an apocalyptic number.

11010303150055 is a deficient number, since it is larger than the sum of its proper divisors (3410863747769).

11010303150055 is a wasteful number, since it uses less digits than its factorization.

11010303150055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 106654706.

The product of its (nonzero) digits is 1125, while the sum is 25.

Adding to 11010303150055 its reverse (55005130301011), we get a palindrome (66015433451066).

The spelling of 11010303150055 in words is "eleven trillion, ten billion, three hundred three million, one hundred fifty thousand, fifty-five".

Divisors: 1 5 11 55 1877 9385 20647 103235 106652813 533264065 1173180943 5865904715 200187330001 1000936650005 2202060630011 11010303150055