Base | Representation |
---|---|
bin | 110011010001010101… |
… | …0000111101101100111 |
3 | 101112012021110200021222 |
4 | 1212202222013231213 |
5 | 3300442400224111 |
6 | 122325232130555 |
7 | 10645313121563 |
oct | 1464252075547 |
9 | 345167420258 |
10 | 110103133031 |
11 | 42770391521 |
12 | 19409396a5b |
13 | a4c8999778 |
14 | 5486b8c6a3 |
15 | 2ce61ba7db |
hex | 19a2a87b67 |
110103133031 has 2 divisors, whose sum is σ = 110103133032. Its totient is φ = 110103133030.
The previous prime is 110103133027. The next prime is 110103133033. The reversal of 110103133031 is 130331301011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110103133031 - 22 = 110103133027 is a prime.
It is a super-2 number, since 2×1101031330312 (a number of 23 digits) contains 22 as substring.
Together with 110103133033, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110103133033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55051566515 + 55051566516.
It is an arithmetic number, because the mean of its divisors is an integer number (55051566516).
Almost surely, 2110103133031 is an apocalyptic number.
110103133031 is a deficient number, since it is larger than the sum of its proper divisors (1).
110103133031 is an equidigital number, since it uses as much as digits as its factorization.
110103133031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 110103133031 its reverse (130331301011), we get a palindrome (240434434042).
The spelling of 110103133031 in words is "one hundred ten billion, one hundred three million, one hundred thirty-three thousand, thirty-one".
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