Base | Representation |
---|---|
bin | 1010000000111000101011… |
… | …0011111111100010011111 |
3 | 1102222120120211111100120110 |
4 | 2200032022303333202133 |
5 | 2420343123444040210 |
6 | 35230024212421103 |
7 | 2214320146244136 |
oct | 240161263774237 |
9 | 42876524440513 |
10 | 11010330065055 |
11 | 3565500312762 |
12 | 1299a61317793 |
13 | 61b367607a99 |
14 | 2a0c8d49691d |
15 | 14160d514420 |
hex | a038acff89f |
11010330065055 has 32 divisors (see below), whose sum is σ = 18689877771264. Its totient is φ = 5515766268416.
The previous prime is 11010330065039. The next prime is 11010330065071. The reversal of 11010330065055 is 55056003301011.
It is an interprime number because it is at equal distance from previous prime (11010330065039) and next prime (11010330065071).
It is a cyclic number.
It is not a de Polignac number, because 11010330065055 - 24 = 11010330065039 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 42791979 + ... + 43048508.
It is an arithmetic number, because the mean of its divisors is an integer number (584058680352).
Almost surely, 211010330065055 is an apocalyptic number.
11010330065055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11010330065055 is a deficient number, since it is larger than the sum of its proper divisors (7679547706209).
11010330065055 is a wasteful number, since it uses less digits than its factorization.
11010330065055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 85841015.
The product of its (nonzero) digits is 6750, while the sum is 30.
Adding to 11010330065055 its reverse (55056003301011), we get a palindrome (66066333366066).
The spelling of 11010330065055 in words is "eleven trillion, ten billion, three hundred thirty million, sixty-five thousand, fifty-five".
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