11010344302031 has 2 divisors, whose sum is σ = 11010344302032. Its totient is φ = 11010344302030.

The previous prime is 11010344301997. The next prime is 11010344302033. The reversal of 11010344302031 is 13020344301011.

11010344302031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11010344302031 - 2³⁰ = 11009270560207 is a prime.

It is a super-2 number, since 2×11010344302031² (a number of 27 digits) contains 22 as substring.

Together with 11010344302033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11010344301988 and 11010344302006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11010344302033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505172151015 + 5505172151016.

It is an arithmetic number, because the mean of its divisors is an integer number (5505172151016).

Almost surely, 2^{11010344302031} is an apocalyptic number.

11010344302031 is a deficient number, since it is larger than the sum of its proper divisors (1).

11010344302031 is an equidigital number, since it uses as much as digits as its factorization.

11010344302031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 11010344302031 its reverse (13020344301011), we get a palindrome (24030688603042).

The spelling of 11010344302031 in words is "eleven trillion, ten billion, three hundred forty-four million, three hundred two thousand, thirty-one".