11011000100207 has 2 divisors, whose sum is σ = 11011000100208. Its totient is φ = 11011000100206.

The previous prime is 11011000100141. The next prime is 11011000100209. The reversal of 11011000100207 is 70200100011011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11011000100207 - 2³² = 11006705132911 is a prime.

Together with 11011000100209, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11011000100191 and 11011000100200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11011000100209) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505500050103 + 5505500050104.

It is an arithmetic number, because the mean of its divisors is an integer number (5505500050104).

Almost surely, 2^{11011000100207} is an apocalyptic number.

11011000100207 is a deficient number, since it is larger than the sum of its proper divisors (1).

11011000100207 is an equidigital number, since it uses as much as digits as its factorization.

11011000100207 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14, while the sum is 14.

Adding to 11011000100207 its reverse (70200100011011), we get a palindrome (81211100111218).

The spelling of 11011000100207 in words is "eleven trillion, eleven billion, one hundred thousand, two hundred seven".