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1101100100143 is a prime number
BaseRepresentation
bin10000000001011110101…
…011100010101000101111
310220021010120002122102111
4100001132223202220233
5121020023111201033
62201501032304451
7142360200265411
oct20013653425057
93807116078374
101101100100143
11394a7933456a
12159498242127
137caaa9926c4
143b4176309b1
151d9973567cd
hex1005eae2a2f

1101100100143 has 2 divisors, whose sum is σ = 1101100100144. Its totient is φ = 1101100100142.

The previous prime is 1101100100083. The next prime is 1101100100147. The reversal of 1101100100143 is 3410010011011.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (3410010011011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1101100100143 - 213 = 1101100091951 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1101100100147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550550050071 + 550550050072.

It is an arithmetic number, because the mean of its divisors is an integer number (550550050072).

Almost surely, 21101100100143 is an apocalyptic number.

1101100100143 is a deficient number, since it is larger than the sum of its proper divisors (1).

1101100100143 is an equidigital number, since it uses as much as digits as its factorization.

1101100100143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 1101100100143 its reverse (3410010011011), we get a palindrome (4511110111154).

The spelling of 1101100100143 in words is "one trillion, one hundred one billion, one hundred million, one hundred thousand, one hundred forty-three".