Base | Representation |
---|---|
bin | 11001000010010100000001… |
… | …011101101000000100101011 |
3 | 112102212102102021012201211002 |
4 | 121002110001131220010223 |
5 | 103413020441341023313 |
6 | 1030103514312425215 |
7 | 32123122644520523 |
oct | 3102240135500453 |
9 | 472772367181732 |
10 | 110110101111083 |
11 | 320a2482570587 |
12 | 104240aa0a820b |
13 | 49594517107b8 |
14 | 1d29500724683 |
15 | cae33a62e058 |
hex | 64250176812b |
110110101111083 has 2 divisors, whose sum is σ = 110110101111084. Its totient is φ = 110110101111082.
The previous prime is 110110101111053. The next prime is 110110101111149. The reversal of 110110101111083 is 380111101011011.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110110101111083 - 218 = 110110100848939 is a prime.
It is a super-2 number, since 2×1101101011110832 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (110110101111053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55055050555541 + 55055050555542.
It is an arithmetic number, because the mean of its divisors is an integer number (55055050555542).
Almost surely, 2110110101111083 is an apocalyptic number.
110110101111083 is a deficient number, since it is larger than the sum of its proper divisors (1).
110110101111083 is an equidigital number, since it uses as much as digits as its factorization.
110110101111083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 20.
Adding to 110110101111083 its reverse (380111101011011), we get a palindrome (490221202122094).
The spelling of 110110101111083 in words is "one hundred ten trillion, one hundred ten billion, one hundred one million, one hundred eleven thousand, eighty-three".
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