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110110101111083 is a prime number
BaseRepresentation
bin11001000010010100000001…
…011101101000000100101011
3112102212102102021012201211002
4121002110001131220010223
5103413020441341023313
61030103514312425215
732123122644520523
oct3102240135500453
9472772367181732
10110110101111083
11320a2482570587
12104240aa0a820b
1349594517107b8
141d29500724683
15cae33a62e058
hex64250176812b

110110101111083 has 2 divisors, whose sum is σ = 110110101111084. Its totient is φ = 110110101111082.

The previous prime is 110110101111053. The next prime is 110110101111149. The reversal of 110110101111083 is 380111101011011.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 110110101111083 - 218 = 110110100848939 is a prime.

It is a super-2 number, since 2×1101101011110832 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (110110101111053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55055050555541 + 55055050555542.

It is an arithmetic number, because the mean of its divisors is an integer number (55055050555542).

Almost surely, 2110110101111083 is an apocalyptic number.

110110101111083 is a deficient number, since it is larger than the sum of its proper divisors (1).

110110101111083 is an equidigital number, since it uses as much as digits as its factorization.

110110101111083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 20.

Adding to 110110101111083 its reverse (380111101011011), we get a palindrome (490221202122094).

The spelling of 110110101111083 in words is "one hundred ten trillion, one hundred ten billion, one hundred one million, one hundred eleven thousand, eighty-three".