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11011122013 is a prime number
BaseRepresentation
bin10100100000101000…
…00110001101011101
31001102101100221202211
422100110012031131
5140022321401023
65020342320421
7536602664353
oct122024061535
931371327684
1011011122013
114740544a41
122173729111
13106631cb18
147665677d3
15446a39a0d
hex29050635d

11011122013 has 2 divisors, whose sum is σ = 11011122014. Its totient is φ = 11011122012.

The previous prime is 11011121983. The next prime is 11011122047. The reversal of 11011122013 is 31022111011.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10573391929 + 437730084 = 102827^2 + 20922^2 .

It is a cyclic number.

It is not a de Polignac number, because 11011122013 - 25 = 11011121981 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11011121984 and 11011122002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11011122053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505561006 + 5505561007.

It is an arithmetic number, because the mean of its divisors is an integer number (5505561007).

Almost surely, 211011122013 is an apocalyptic number.

It is an amenable number.

11011122013 is a deficient number, since it is larger than the sum of its proper divisors (1).

11011122013 is an equidigital number, since it uses as much as digits as its factorization.

11011122013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 11011122013 its reverse (31022111011), we get a palindrome (42033233024).

The spelling of 11011122013 in words is "eleven billion, eleven million, one hundred twenty-two thousand, thirteen".