11011213181 has 2 divisors, whose sum is σ = 11011213182. Its totient is φ = 11011213180.

The previous prime is 11011213133. The next prime is 11011213183. The reversal of 11011213181 is 18131211011.

11011213181 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8886832900 + 2124380281 = 94270^2 + 46091^2 .

It is a cyclic number.

It is not a de Polignac number, because 11011213181 - 2¹⁴ = 11011196797 is a prime.

It is a super-2 number, since 2×11011213181² (a number of 21 digits) contains 22 as substring.

Together with 11011213183, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11011213183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505606590 + 5505606591.

It is an arithmetic number, because the mean of its divisors is an integer number (5505606591).

Almost surely, 2^11011213181 is an apocalyptic number.

It is an amenable number.

11011213181 is a deficient number, since it is larger than the sum of its proper divisors (1).

11011213181 is an equidigital number, since it uses as much as digits as its factorization.

11011213181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 20.

Adding to 11011213181 its reverse (18131211011), we get a palindrome (29142424192).

The spelling of 11011213181 in words is "eleven billion, eleven million, two hundred thirteen thousand, one hundred eighty-one".