110113101101 has 2 divisors, whose sum is σ = 110113101102. Its totient is φ = 110113101100.

The previous prime is 110113101079. The next prime is 110113101103. The reversal of 110113101101 is 101101311011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 62051308201 + 48061792900 = 249101^2 + 219230^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-110113101101 is a prime.

Together with 110113101103, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110113101103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55056550550 + 55056550551.

It is an arithmetic number, because the mean of its divisors is an integer number (55056550551).

Almost surely, 2^110113101101 is an apocalyptic number.

It is an amenable number.

110113101101 is a deficient number, since it is larger than the sum of its proper divisors (1).

110113101101 is an equidigital number, since it uses as much as digits as its factorization.

110113101101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 11.

Adding to 110113101101 its reverse (101101311011), we get a palindrome (211214412112).

The spelling of 110113101101 in words is "one hundred ten billion, one hundred thirteen million, one hundred one thousand, one hundred one".