Base | Representation |
---|---|
bin | 10000000001100000100… |
… | …010100110111110011001 |
3 | 10220021012201211102111001 |
4 | 100001200202212332121 |
5 | 121020104104004144 |
6 | 2201504105305001 |
7 | 142361026505215 |
oct | 20014042467631 |
9 | 3807181742431 |
10 | 1101131313049 |
11 | 394a94a13259 |
12 | 1594a6795161 |
13 | 7cab42a0791 |
14 | 3b41b837945 |
15 | 1d999e6ebd4 |
hex | 100608a6f99 |
1101131313049 has 2 divisors, whose sum is σ = 1101131313050. Its totient is φ = 1101131313048.
The previous prime is 1101131312993. The next prime is 1101131313071. The reversal of 1101131313049 is 9403131311011.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1099652141449 + 1479171600 = 1048643^2 + 38460^2 .
It is a cyclic number.
It is not a de Polignac number, because 1101131313049 - 29 = 1101131312537 is a prime.
It is not a weakly prime, because it can be changed into another prime (1101131317049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550565656524 + 550565656525.
It is an arithmetic number, because the mean of its divisors is an integer number (550565656525).
Almost surely, 21101131313049 is an apocalyptic number.
It is an amenable number.
1101131313049 is a deficient number, since it is larger than the sum of its proper divisors (1).
1101131313049 is an equidigital number, since it uses as much as digits as its factorization.
1101131313049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 28.
The spelling of 1101131313049 in words is "one trillion, one hundred one billion, one hundred thirty-one million, three hundred thirteen thousand, forty-nine".
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