110120000041 has 2 divisors, whose sum is σ = 110120000042. Its totient is φ = 110120000040.

The previous prime is 110119999993. The next prime is 110120000051. The reversal of 110120000041 is 140000021011.

It is an a-pointer prime, because the next prime (110120000051) can be obtained adding 110120000041 to its sum of digits (10).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 68436652816 + 41683347225 = 261604^2 + 204165^2 .

It is a cyclic number.

It is not a de Polignac number, because 110120000041 - 2¹⁵ = 110119967273 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110119999982 and 110120000027.

It is not a weakly prime, because it can be changed into another prime (110120000051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55060000020 + 55060000021.

It is an arithmetic number, because the mean of its divisors is an integer number (55060000021).

Almost surely, 2^110120000041 is an apocalyptic number.

It is an amenable number.

110120000041 is a deficient number, since it is larger than the sum of its proper divisors (1).

110120000041 is an equidigital number, since it uses as much as digits as its factorization.

110120000041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8, while the sum is 10.

Adding to 110120000041 its reverse (140000021011), we get a palindrome (250120021052).

The spelling of 110120000041 in words is "one hundred ten billion, one hundred twenty million, forty-one", and thus it is an aban number.