11012013431 has 2 divisors, whose sum is σ = 11012013432. Its totient is φ = 11012013430.

The previous prime is 11012013373. The next prime is 11012013433. The reversal of 11012013431 is 13431021011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11012013431 - 2²⁶ = 10944904567 is a prime.

It is a super-4 number, since 4×11012013431⁴ (a number of 41 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

Together with 11012013433, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11012013433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506006715 + 5506006716.

It is an arithmetic number, because the mean of its divisors is an integer number (5506006716).

Almost surely, 2^11012013431 is an apocalyptic number.

11012013431 is a deficient number, since it is larger than the sum of its proper divisors (1).

11012013431 is an equidigital number, since it uses as much as digits as its factorization.

11012013431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 11012013431 its reverse (13431021011), we get a palindrome (24443034442).

The spelling of 11012013431 in words is "eleven billion, twelve million, thirteen thousand, four hundred thirty-one".