Base | Representation |
---|---|
bin | 10000000001100101010… |
… | …110110100110100000111 |
3 | 10220021102100212100011221 |
4 | 100001211112310310013 |
5 | 121020240300010322 |
6 | 2201520113141211 |
7 | 142363030331125 |
oct | 20014526646407 |
9 | 3807370770157 |
10 | 1101212110087 |
11 | 395026589271 |
12 | 15950985a807 |
13 | 7cac7c4c88b |
14 | 3b42846a915 |
15 | 1d9a20ce9c7 |
hex | 100655b4d07 |
1101212110087 has 2 divisors, whose sum is σ = 1101212110088. Its totient is φ = 1101212110086.
The previous prime is 1101212109973. The next prime is 1101212110111. The reversal of 1101212110087 is 7800112121011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1101212110087 - 211 = 1101212108039 is a prime.
It is a super-2 number, since 2×11012121100872 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1101212116087) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550606055043 + 550606055044.
It is an arithmetic number, because the mean of its divisors is an integer number (550606055044).
Almost surely, 21101212110087 is an apocalyptic number.
1101212110087 is a deficient number, since it is larger than the sum of its proper divisors (1).
1101212110087 is an equidigital number, since it uses as much as digits as its factorization.
1101212110087 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 224, while the sum is 25.
Adding to 1101212110087 its reverse (7800112121011), we get a palindrome (8901324231098).
The spelling of 1101212110087 in words is "one trillion, one hundred one billion, two hundred twelve million, one hundred ten thousand, eighty-seven".
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