Base | Representation |
---|---|
bin | 1010000000111111011001… |
… | …0010011010000100111111 |
3 | 1102222202020111102002222021 |
4 | 2200033312102122010333 |
5 | 2420410322044401231 |
6 | 35230523144101011 |
7 | 2214412632526654 |
oct | 240176622320477 |
9 | 42882214362867 |
10 | 11012133200191 |
11 | 3566246118892 |
12 | 129a285164767 |
13 | 61b594054b56 |
14 | 2a0dc0b47c2b |
15 | 1416b698b811 |
hex | a03f649a13f |
11012133200191 has 2 divisors, whose sum is σ = 11012133200192. Its totient is φ = 11012133200190.
The previous prime is 11012133200093. The next prime is 11012133200197. The reversal of 11012133200191 is 19100233121011.
11012133200191 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11012133200191 - 27 = 11012133200063 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11012133200197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506066600095 + 5506066600096.
It is an arithmetic number, because the mean of its divisors is an integer number (5506066600096).
Almost surely, 211012133200191 is an apocalyptic number.
11012133200191 is a deficient number, since it is larger than the sum of its proper divisors (1).
11012133200191 is an equidigital number, since it uses as much as digits as its factorization.
11012133200191 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 25.
The spelling of 11012133200191 in words is "eleven trillion, twelve billion, one hundred thirty-three million, two hundred thousand, one hundred ninety-one".
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