Base | Representation |
---|---|
bin | 10100100000110000… |
… | …10010010011101111 |
3 | 1001102110102202010022 |
4 | 22100120102103233 |
5 | 140023112021033 |
6 | 5020422032355 |
7 | 536615220041 |
oct | 122030222357 |
9 | 31373382108 |
10 | 11012220143 |
11 | 4741124a91 |
12 | 2173b786bb |
13 | 10666158c2 |
14 | 766771a91 |
15 | 446ba5098 |
hex | 2906124ef |
11012220143 has 2 divisors, whose sum is σ = 11012220144. Its totient is φ = 11012220142.
The previous prime is 11012220103. The next prime is 11012220161. The reversal of 11012220143 is 34102221011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11012220143 - 216 = 11012154607 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11012220103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506110071 + 5506110072.
It is an arithmetic number, because the mean of its divisors is an integer number (5506110072).
Almost surely, 211012220143 is an apocalyptic number.
11012220143 is a deficient number, since it is larger than the sum of its proper divisors (1).
11012220143 is an equidigital number, since it uses as much as digits as its factorization.
11012220143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 11012220143 its reverse (34102221011), we get a palindrome (45114441154).
The spelling of 11012220143 in words is "eleven billion, twelve million, two hundred twenty thousand, one hundred forty-three".
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