Base | Representation |
---|---|
bin | 1010000001000000000001… |
… | …0000100111110000101111 |
3 | 1102222202200011020000210202 |
4 | 2200100000100213300233 |
5 | 2420411142412112421 |
6 | 35230551522024115 |
7 | 2214420033556334 |
oct | 240200020476057 |
9 | 42882604200722 |
10 | 11012300504111 |
11 | 35663215a9795 |
12 | 129a3111a803b |
13 | 61b5bc901c5a |
14 | 2a0dd905898b |
15 | 1416c64d810b |
hex | a0400427c2f |
11012300504111 has 2 divisors, whose sum is σ = 11012300504112. Its totient is φ = 11012300504110.
The previous prime is 11012300504059. The next prime is 11012300504113. The reversal of 11012300504111 is 11140500321011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11012300504111 - 242 = 6614253993007 is a prime.
Together with 11012300504113, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11012300504113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506150252055 + 5506150252056.
It is an arithmetic number, because the mean of its divisors is an integer number (5506150252056).
Almost surely, 211012300504111 is an apocalyptic number.
11012300504111 is a deficient number, since it is larger than the sum of its proper divisors (1).
11012300504111 is an equidigital number, since it uses as much as digits as its factorization.
11012300504111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120, while the sum is 20.
Adding to 11012300504111 its reverse (11140500321011), we get a palindrome (22152800825122).
The spelling of 11012300504111 in words is "eleven trillion, twelve billion, three hundred million, five hundred four thousand, one hundred eleven".
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