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1101243340132 = 221321177756541
BaseRepresentation
bin10000000001100111001…
…101111101010101100100
310220021111112121222202021
4100001213031331111210
5121020321243341012
62201523150352524
7142363556641615
oct20014715752544
93807445558667
101101243340132
11395042179921
121595181bb744
137cb015656b0
143b42c679c0c
151d9a4bed007
hex1006737d564

1101243340132 has 12 divisors (see below), whose sum is σ = 2075420141116. Its totient is φ = 508266156960.

The previous prime is 1101243340073. The next prime is 1101243340157. The reversal of 1101243340132 is 2310433421011.

It can be written as a sum of positive squares in 2 ways, for example, as 653342423616 + 447900916516 = 808296^2 + 669254^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1101243340097 and 1101243340106.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10588878219 + ... + 10588878322.

Almost surely, 21101243340132 is an apocalyptic number.

It is an amenable number.

1101243340132 is a deficient number, since it is larger than the sum of its proper divisors (974176800984).

1101243340132 is a wasteful number, since it uses less digits than its factorization.

1101243340132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21177756558 (or 21177756556 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1101243340132 its reverse (2310433421011), we get a palindrome (3411676761143).

The spelling of 1101243340132 in words is "one trillion, one hundred one billion, two hundred forty-three million, three hundred forty thousand, one hundred thirty-two".

Divisors: 1 2 4 13 26 52 21177756541 42355513082 84711026164 275310835033 550621670066 1101243340132