Base | Representation |
---|---|
bin | 1010000001000010111111… |
… | …1110110001110011100111 |
3 | 1102222211201221202012012201 |
4 | 2200100233332301303213 |
5 | 2420414312342224111 |
6 | 35231203202155331 |
7 | 2214445625032414 |
oct | 240205776616347 |
9 | 42884657665181 |
10 | 11013101133031 |
11 | 35666a252a088 |
12 | 129a4b5352b47 |
13 | 61b6b974518a |
14 | 2a107350910b |
15 | 1417219366c1 |
hex | a042ffb1ce7 |
11013101133031 has 2 divisors, whose sum is σ = 11013101133032. Its totient is φ = 11013101133030.
The previous prime is 11013101133011. The next prime is 11013101133091. The reversal of 11013101133031 is 13033110131011.
It is a weak prime.
It is an emirp because it is prime and its reverse (13033110131011) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11013101133031 is a prime.
It is a super-2 number, since 2×110131011330312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11013101133011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506550566515 + 5506550566516.
It is an arithmetic number, because the mean of its divisors is an integer number (5506550566516).
Almost surely, 211013101133031 is an apocalyptic number.
11013101133031 is a deficient number, since it is larger than the sum of its proper divisors (1).
11013101133031 is an equidigital number, since it uses as much as digits as its factorization.
11013101133031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 19.
Adding to 11013101133031 its reverse (13033110131011), we get a palindrome (24046211264042).
The spelling of 11013101133031 in words is "eleven trillion, thirteen billion, one hundred one million, one hundred thirty-three thousand, thirty-one".
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