Base | Representation |
---|---|
bin | 1011110110101000000111… |
… | …1001100101000101000011 |
3 | 1201010221201212001110100001 |
4 | 2331222001321211011003 |
5 | 3202013302143143021 |
6 | 43415154513340431 |
7 | 2513416422151525 |
oct | 275520171450503 |
9 | 51127655043301 |
10 | 13033110131011 |
11 | 4175346995233 |
12 | 1565aa2267717 |
13 | 73702b4b4909 |
14 | 330b3d543a15 |
15 | 17904b35b091 |
hex | bda81e65143 |
13033110131011 has 2 divisors, whose sum is σ = 13033110131012. Its totient is φ = 13033110131010.
The previous prime is 13033110130973. The next prime is 13033110131123. The reversal of 13033110131011 is 11013101133031.
It is a weak prime.
It is an emirp because it is prime and its reverse (11013101133031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13033110131011 - 211 = 13033110128963 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13033110131011.
It is not a weakly prime, because it can be changed into another prime (13033110131611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516555065505 + 6516555065506.
It is an arithmetic number, because the mean of its divisors is an integer number (6516555065506).
Almost surely, 213033110131011 is an apocalyptic number.
13033110131011 is a deficient number, since it is larger than the sum of its proper divisors (1).
13033110131011 is an equidigital number, since it uses as much as digits as its factorization.
13033110131011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81, while the sum is 19.
Adding to 13033110131011 its reverse (11013101133031), we get a palindrome (24046211264042).
The spelling of 13033110131011 in words is "thirteen trillion, thirty-three billion, one hundred ten million, one hundred thirty-one thousand, eleven".
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