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1101311023301 is a prime number
BaseRepresentation
bin10000000001101011010…
…000001001100011000101
310220021200020222122121022
4100001223100021203011
5121020441110221201
62201534005200525
7142365341145626
oct20015320114305
93807606878538
101101311023301
113950773a8225
12159536a00145
137cb125a27c8
143b437657a4d
151d9aab1c41b
hex1006b4098c5

1101311023301 has 2 divisors, whose sum is σ = 1101311023302. Its totient is φ = 1101311023300.

The previous prime is 1101311023291. The next prime is 1101311023303. The reversal of 1101311023301 is 1033201131011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1054371634276 + 46939389025 = 1026826^2 + 216655^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1101311023301 is a prime.

Together with 1101311023303, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1101311023301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1101311023303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550655511650 + 550655511651.

It is an arithmetic number, because the mean of its divisors is an integer number (550655511651).

Almost surely, 21101311023301 is an apocalyptic number.

It is an amenable number.

1101311023301 is a deficient number, since it is larger than the sum of its proper divisors (1).

1101311023301 is an equidigital number, since it uses as much as digits as its factorization.

1101311023301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1101311023301 its reverse (1033201131011), we get a palindrome (2134512154312).

The spelling of 1101311023301 in words is "one trillion, one hundred one billion, three hundred eleven million, twenty-three thousand, three hundred one".