Base | Representation |
---|---|
bin | 1010000001000011000100… |
… | …1010100110110110101111 |
3 | 1102222211210100011002211012 |
4 | 2200100301022212312233 |
5 | 2420414332434323434 |
6 | 35231205152215435 |
7 | 2214446256013133 |
oct | 240206112466657 |
9 | 42884710132735 |
10 | 11013121011119 |
11 | 3566702776857 |
12 | 129a4bbb3a57b |
13 | 61b6c08b4c66 |
14 | 2a10760013c3 |
15 | 1417235613ce |
hex | a04312a6daf |
11013121011119 has 2 divisors, whose sum is σ = 11013121011120. Its totient is φ = 11013121011118.
The previous prime is 11013121011043. The next prime is 11013121011133. The reversal of 11013121011119 is 91111012131011.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11013121011119 - 212 = 11013121007023 is a prime.
It is a super-2 number, since 2×110131210111192 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11013121011094 and 11013121011103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11013120011119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506560505559 + 5506560505560.
It is an arithmetic number, because the mean of its divisors is an integer number (5506560505560).
Almost surely, 211013121011119 is an apocalyptic number.
11013121011119 is a deficient number, since it is larger than the sum of its proper divisors (1).
11013121011119 is an equidigital number, since it uses as much as digits as its factorization.
11013121011119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 23.
The spelling of 11013121011119 in words is "eleven trillion, thirteen billion, one hundred twenty-one million, eleven thousand, one hundred nineteen".
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