Base | Representation |
---|---|
bin | 10100100000111000… |
… | …00111101101000111 |
3 | 1001102112022210220212 |
4 | 22100130013231013 |
5 | 140023341202122 |
6 | 5020455350035 |
7 | 536626604351 |
oct | 122034075507 |
9 | 31375283825 |
10 | 11013225287 |
11 | 4741751189 |
12 | 217438231b |
13 | 10668a826c |
14 | 7669540d1 |
15 | 446d02ce2 |
hex | 290707b47 |
11013225287 has 2 divisors, whose sum is σ = 11013225288. Its totient is φ = 11013225286.
The previous prime is 11013225283. The next prime is 11013225329. The reversal of 11013225287 is 78252231011.
It is a weak prime.
It is an emirp because it is prime and its reverse (78252231011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11013225287 - 22 = 11013225283 is a prime.
It is a super-2 number, since 2×110132252872 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11013225283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506612643 + 5506612644.
It is an arithmetic number, because the mean of its divisors is an integer number (5506612644).
Almost surely, 211013225287 is an apocalyptic number.
11013225287 is a deficient number, since it is larger than the sum of its proper divisors (1).
11013225287 is an equidigital number, since it uses as much as digits as its factorization.
11013225287 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6720, while the sum is 32.
Adding to 11013225287 its reverse (78252231011), we get a palindrome (89265456298).
The spelling of 11013225287 in words is "eleven billion, thirteen million, two hundred twenty-five thousand, two hundred eighty-seven".
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