Base | Representation |
---|---|
bin | 10000000001101101101… |
… | …001100101001010100101 |
3 | 10220021210001200002122121 |
4 | 100001231221211022211 |
5 | 121021031404310303 |
6 | 2201542003225541 |
7 | 142366340054515 |
oct | 20015551451245 |
9 | 3807701602577 |
10 | 1101351244453 |
11 | 395098079a49 |
12 | 1595483782b1 |
13 | 7cb1aa15bc5 |
14 | 3b43cb27845 |
15 | 1d9ae4149bd |
hex | 1006da652a5 |
1101351244453 has 2 divisors, whose sum is σ = 1101351244454. Its totient is φ = 1101351244452.
The previous prime is 1101351244439. The next prime is 1101351244529. The reversal of 1101351244453 is 3544421531011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1038509779329 + 62841465124 = 1019073^2 + 250682^2 .
It is a cyclic number.
It is not a de Polignac number, because 1101351244453 - 213 = 1101351236261 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1101351247453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550675622226 + 550675622227.
It is an arithmetic number, because the mean of its divisors is an integer number (550675622227).
Almost surely, 21101351244453 is an apocalyptic number.
It is an amenable number.
1101351244453 is a deficient number, since it is larger than the sum of its proper divisors (1).
1101351244453 is an equidigital number, since it uses as much as digits as its factorization.
1101351244453 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 28800, while the sum is 34.
Adding to 1101351244453 its reverse (3544421531011), we get a palindrome (4645772775464).
The spelling of 1101351244453 in words is "one trillion, one hundred one billion, three hundred fifty-one million, two hundred forty-four thousand, four hundred fifty-three".
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