Base | Representation |
---|---|
bin | 1010000001000111001000… |
… | …1101001100110101101111 |
3 | 1102222221121101102202022201 |
4 | 2200101302031030311233 |
5 | 2420424101311210111 |
6 | 35231505332322331 |
7 | 2214515306032102 |
oct | 240216215146557 |
9 | 42887541382281 |
10 | 11014212210031 |
11 | 356711271a738 |
12 | 129a7654733a7 |
13 | 61b8359a39a4 |
14 | 2a113accc739 |
15 | 1417892596c1 |
hex | a047234cd6f |
11014212210031 has 2 divisors, whose sum is σ = 11014212210032. Its totient is φ = 11014212210030.
The previous prime is 11014212209947. The next prime is 11014212210037. The reversal of 11014212210031 is 13001221241011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11014212210031 - 227 = 11014077992303 is a prime.
It is a super-2 number, since 2×110142122100312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11014212209990 and 11014212210008.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11014212210037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5507106105015 + 5507106105016.
It is an arithmetic number, because the mean of its divisors is an integer number (5507106105016).
Almost surely, 211014212210031 is an apocalyptic number.
11014212210031 is a deficient number, since it is larger than the sum of its proper divisors (1).
11014212210031 is an equidigital number, since it uses as much as digits as its factorization.
11014212210031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 11014212210031 its reverse (13001221241011), we get a palindrome (24015433451042).
The spelling of 11014212210031 in words is "eleven trillion, fourteen billion, two hundred twelve million, two hundred ten thousand, thirty-one".
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