1101443434130 has 24 divisors (see below), whose sum is σ = 2146837087332. Its totient is φ = 406686805824.

The previous prime is 1101443434093. The next prime is 1101443434139. The reversal of 1101443434130 is 314343441011.

It can be written as a sum of positive squares in 6 ways, for example, as 187486402009 + 913957032121 = 432997^2 + 956011^2 .

It is a super-3 number, since 3×1101443434130³ (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1101443434093 and 1101443434102.

It is not an unprimeable number, because it can be changed into a prime (1101443434139) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 325869149 + ... + 325872528.

Almost surely, 2^{1101443434130} is an apocalyptic number.

1101443434130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1101443434130 is a deficient number, since it is larger than the sum of its proper divisors (1045393653202).

1101443434130 is a wasteful number, since it uses less digits than its factorization.

1101443434130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 651741710 (or 651741697 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1101443434130 its reverse (314343441011), we get a palindrome (1415786875141).

The spelling of 1101443434130 in words is "one trillion, one hundred one billion, four hundred forty-three million, four hundred thirty-four thousand, one hundred thirty".