Base | Representation |
---|---|
bin | 11001000011001000100010… |
… | …000001110101101100001011 |
3 | 112110001210221112220011210122 |
4 | 121003020202001311230023 |
5 | 103414431423401043203 |
6 | 1030145441055533455 |
7 | 32130160060554254 |
oct | 3103104201655413 |
9 | 473053845804718 |
10 | 110166482049803 |
11 | 321143850a0303 |
12 | 10433003b2a28b |
13 | 49618684457ba |
14 | 1d2c12c6a5b2b |
15 | cb0a3a2a7538 |
hex | 643222075b0b |
110166482049803 has 2 divisors, whose sum is σ = 110166482049804. Its totient is φ = 110166482049802.
The previous prime is 110166482049769. The next prime is 110166482049817. The reversal of 110166482049803 is 308940284661011.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110166482049803 - 230 = 110165408307979 is a prime.
It is not a weakly prime, because it can be changed into another prime (110166482040803) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55083241024901 + 55083241024902.
It is an arithmetic number, because the mean of its divisors is an integer number (55083241024902).
Almost surely, 2110166482049803 is an apocalyptic number.
110166482049803 is a deficient number, since it is larger than the sum of its proper divisors (1).
110166482049803 is an equidigital number, since it uses as much as digits as its factorization.
110166482049803 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1990656, while the sum is 53.
The spelling of 110166482049803 in words is "one hundred ten trillion, one hundred sixty-six billion, four hundred eighty-two million, forty-nine thousand, eight hundred three".
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