Base | Representation |
---|---|
bin | 1010000001011101000111… |
… | …0011110000111001001001 |
3 | 1110000111211111021112021112 |
4 | 2200113101303300321021 |
5 | 2421023141421400433 |
6 | 35234322534420105 |
7 | 2215114424664131 |
oct | 240272163607111 |
9 | 43014744245245 |
10 | 11020111121993 |
11 | 356966a486596 |
12 | 129b930b01635 |
13 | 61c265b3793c |
14 | 2a153a505ac1 |
15 | 1419d2075348 |
hex | a05d1cf0e49 |
11020111121993 has 2 divisors, whose sum is σ = 11020111121994. Its totient is φ = 11020111121992.
The previous prime is 11020111121963. The next prime is 11020111122061. The reversal of 11020111121993 is 39912111102011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10555461672889 + 464649449104 = 3248917^2 + 681652^2 .
It is a cyclic number.
It is not a de Polignac number, because 11020111121993 - 228 = 11019842686537 is a prime.
It is a super-4 number, since 4×110201111219934 (a number of 53 digits) contains 4444 as substring.
It is not a weakly prime, because it can be changed into another prime (11020111121963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5510055560996 + 5510055560997.
It is an arithmetic number, because the mean of its divisors is an integer number (5510055560997).
Almost surely, 211020111121993 is an apocalyptic number.
It is an amenable number.
11020111121993 is a deficient number, since it is larger than the sum of its proper divisors (1).
11020111121993 is an equidigital number, since it uses as much as digits as its factorization.
11020111121993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 32.
The spelling of 11020111121993 in words is "eleven trillion, twenty billion, one hundred eleven million, one hundred twenty-one thousand, nine hundred ninety-three".
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