110206411331 has 2 divisors, whose sum is σ = 110206411332. Its totient is φ = 110206411330.

The previous prime is 110206411321. The next prime is 110206411333. The reversal of 110206411331 is 133114602011.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-110206411331 is a prime.

It is a super-2 number, since 2×110206411331² (a number of 23 digits) contains 22 as substring.

Together with 110206411333, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 110206411297 and 110206411306.

It is not a weakly prime, because it can be changed into another prime (110206411333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55103205665 + 55103205666.

It is an arithmetic number, because the mean of its divisors is an integer number (55103205666).

Almost surely, 2^110206411331 is an apocalyptic number.

110206411331 is a deficient number, since it is larger than the sum of its proper divisors (1).

110206411331 is an equidigital number, since it uses as much as digits as its factorization.

110206411331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 23.

The spelling of 110206411331 in words is "one hundred ten billion, two hundred six million, four hundred eleven thousand, three hundred thirty-one".