Base | Representation |
---|---|
bin | 10000000010011010010… |
… | …110000110010100111111 |
3 | 10220100201022200022201102 |
4 | 100002122112012110333 |
5 | 121024100341042002 |
6 | 2202144231403315 |
7 | 142424043612611 |
oct | 20023226062477 |
9 | 3810638608642 |
10 | 1102101112127 |
11 | 3954423896a4 |
12 | 15971752353b |
13 | 7cc0a1953a2 |
14 | 3b4b0562db1 |
15 | 1da05187a02 |
hex | 1009a58653f |
1102101112127 has 2 divisors, whose sum is σ = 1102101112128. Its totient is φ = 1102101112126.
The previous prime is 1102101112121. The next prime is 1102101112139. The reversal of 1102101112127 is 7212111012011.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1102101112127 - 28 = 1102101111871 is a prime.
It is a super-2 number, since 2×11021011121272 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1102101112099 and 1102101112108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1102101112121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551050556063 + 551050556064.
It is an arithmetic number, because the mean of its divisors is an integer number (551050556064).
Almost surely, 21102101112127 is an apocalyptic number.
1102101112127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1102101112127 is an equidigital number, since it uses as much as digits as its factorization.
1102101112127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 20.
Adding to 1102101112127 its reverse (7212111012011), we get a palindrome (8314212124138).
The spelling of 1102101112127 in words is "one trillion, one hundred two billion, one hundred one million, one hundred twelve thousand, one hundred twenty-seven".
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