Base | Representation |
---|---|
bin | 1010000001100000110101… |
… | …0110111111011000101011 |
3 | 1110000121102010020120022021 |
4 | 2200120031112333120223 |
5 | 2421032213203242024 |
6 | 35235010024405311 |
7 | 2215151246055316 |
oct | 240301526773053 |
9 | 43017363216267 |
10 | 11021110212139 |
11 | 356a032438825 |
12 | 129bb6b616837 |
13 | 61c394b16941 |
14 | 2a15d309797d |
15 | 141a3eb26de4 |
hex | a060d5bf62b |
11021110212139 has 2 divisors, whose sum is σ = 11021110212140. Its totient is φ = 11021110212138.
The previous prime is 11021110212043. The next prime is 11021110212149. The reversal of 11021110212139 is 93121201112011.
It is a happy number.
11021110212139 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11021110212139 - 217 = 11021110081067 is a prime.
It is a super-2 number, since 2×110211102121392 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11021110212149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5510555106069 + 5510555106070.
It is an arithmetic number, because the mean of its divisors is an integer number (5510555106070).
Almost surely, 211021110212139 is an apocalyptic number.
11021110212139 is a deficient number, since it is larger than the sum of its proper divisors (1).
11021110212139 is an equidigital number, since it uses as much as digits as its factorization.
11021110212139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 25.
The spelling of 11021110212139 in words is "eleven trillion, twenty-one billion, one hundred ten million, two hundred twelve thousand, one hundred thirty-nine".
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