Base | Representation |
---|---|
bin | 1010000001100000111101… |
… | …0110011111010100010111 |
3 | 1110000121111110010122011021 |
4 | 2200120033112133110113 |
5 | 2421032300232311343 |
6 | 35235013221022011 |
7 | 2215152133131601 |
oct | 240301726372427 |
9 | 43017443118137 |
10 | 11021143635223 |
11 | 356a04a297007 |
12 | 129bb7a854907 |
13 | 61c39ba19a07 |
14 | 2a15d76b8171 |
15 | 141a42a2a0ed |
hex | a060f59f517 |
11021143635223 has 2 divisors, whose sum is σ = 11021143635224. Its totient is φ = 11021143635222.
The previous prime is 11021143635149. The next prime is 11021143635239. The reversal of 11021143635223 is 32253634112011.
11021143635223 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11021143635223 - 225 = 11021110080791 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11021143635253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5510571817611 + 5510571817612.
It is an arithmetic number, because the mean of its divisors is an integer number (5510571817612).
Almost surely, 211021143635223 is an apocalyptic number.
11021143635223 is a deficient number, since it is larger than the sum of its proper divisors (1).
11021143635223 is an equidigital number, since it uses as much as digits as its factorization.
11021143635223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25920, while the sum is 34.
Adding to 11021143635223 its reverse (32253634112011), we get a palindrome (43274777747234).
The spelling of 11021143635223 in words is "eleven trillion, twenty-one billion, one hundred forty-three million, six hundred thirty-five thousand, two hundred twenty-three".
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