Search a number
-
+
110212201101012 = 22352317560898837
BaseRepresentation
bin11001000011110011000111…
…000110001011011011010100
3112110020011221210100121200120
4121003303013012023123110
5103421204041440213022
61030222441453511540
732133366041231613
oct3103630706133324
9473204853317616
10110212201101012
113213180632814a
121043ba431a25b0
134965c7330661a
141d3042862b87a
15cb1d13dccd5c
hex643cc718b6d4

110212201101012 has 24 divisors (see below), whose sum is σ = 257653507751136. Its totient is φ = 36667156769568.

The previous prime is 110212201100977. The next prime is 110212201101019. The reversal of 110212201101012 is 210101102212011.

It is a happy number.

It is a super-3 number, since 3×1102122011010123 (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110212201100982 and 110212201101000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110212201101019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8780443143 + ... + 8780455694.

It is an arithmetic number, because the mean of its divisors is an integer number (10735562822964).

Almost surely, 2110212201101012 is an apocalyptic number.

110212201101012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

110212201101012 is an abundant number, since it is smaller than the sum of its proper divisors (147441306650124).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

110212201101012 is a wasteful number, since it uses less digits than its factorization.

110212201101012 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17560899367 (or 17560899365 counting only the distinct ones).

The product of its (nonzero) digits is 16, while the sum is 15.

Adding to 110212201101012 its reverse (210101102212011), we get a palindrome (320313303313023).

The spelling of 110212201101012 in words is "one hundred ten trillion, two hundred twelve billion, two hundred one million, one hundred one thousand, twelve".

Divisors: 1 2 3 4 6 12 523 1046 1569 2092 3138 6276 17560898837 35121797674 52682696511 70243595348 105365393022 210730786044 9184350091751 18368700183502 27553050275253 36737400367004 55106100550506 110212201101012