Base | Representation |
---|---|
bin | 10100100001110101… |
… | …01010010001111111 |
3 | 1001110002101120000022 |
4 | 22100322222101333 |
5 | 140032413344411 |
6 | 5021343122355 |
7 | 540054630323 |
oct | 122072522177 |
9 | 31402346008 |
10 | 11021231231 |
11 | 474621a16a |
12 | 2176ba33bb |
13 | 106844c2ca |
14 | 767a39983 |
15 | 447884edb |
hex | 290eaa47f |
11021231231 has 2 divisors, whose sum is σ = 11021231232. Its totient is φ = 11021231230.
The previous prime is 11021231213. The next prime is 11021231233. The reversal of 11021231231 is 13213212011.
Together with previous prime (11021231213) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11021231231 - 226 = 10954122367 is a prime.
It is a super-2 number, since 2×110212312312 (a number of 21 digits) contains 22 as substring.
Together with 11021231233, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11021231233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5510615615 + 5510615616.
It is an arithmetic number, because the mean of its divisors is an integer number (5510615616).
Almost surely, 211021231231 is an apocalyptic number.
11021231231 is a deficient number, since it is larger than the sum of its proper divisors (1).
11021231231 is an equidigital number, since it uses as much as digits as its factorization.
11021231231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 11021231231 its reverse (13213212011), we get a palindrome (24234443242).
The spelling of 11021231231 in words is "eleven billion, twenty-one million, two hundred thirty-one thousand, two hundred thirty-one".
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