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110213001300341 is a prime number
BaseRepresentation
bin11001000011110011110110…
…110010101100100101110101
3112110020021000120001221210202
4121003303312302230211311
5103421212211313102331
61030223053120530245
732133424625635352
oct3103636662544565
9473207016057722
10110213001300341
1132132086a94805
1210440027180985
134966070029154
141d304a2a09629
15cb1d5e293ecb
hex643cf6cac975

110213001300341 has 2 divisors, whose sum is σ = 110213001300342. Its totient is φ = 110213001300340.

The previous prime is 110213001300289. The next prime is 110213001300343. The reversal of 110213001300341 is 143003100312011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 99422735499025 + 10790265801316 = 9971095^2 + 3284854^2 .

It is a cyclic number.

It is not a de Polignac number, because 110213001300341 - 230 = 110211927558517 is a prime.

Together with 110213001300343, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110213001300343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55106500650170 + 55106500650171.

It is an arithmetic number, because the mean of its divisors is an integer number (55106500650171).

Almost surely, 2110213001300341 is an apocalyptic number.

It is an amenable number.

110213001300341 is a deficient number, since it is larger than the sum of its proper divisors (1).

110213001300341 is an equidigital number, since it uses as much as digits as its factorization.

110213001300341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 110213001300341 its reverse (143003100312011), we get a palindrome (253216101612352).

The spelling of 110213001300341 in words is "one hundred ten trillion, two hundred thirteen billion, one million, three hundred thousand, three hundred forty-one".