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110213312021 is a prime number
BaseRepresentation
bin110011010100100111…
…0011010111000010101
3101112110221210100110022
41212221032122320111
53301204101441041
6122344205434525
710651121460251
oct1465116327025
9345427710408
10110213312021
11428175a563a
121943a26ba45
13a515765437
14549766d261
152d00bd124b
hex19a939ae15

110213312021 has 2 divisors, whose sum is σ = 110213312022. Its totient is φ = 110213312020.

The previous prime is 110213311991. The next prime is 110213312023. The reversal of 110213312021 is 120213312011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 55714409521 + 54498902500 = 236039^2 + 233450^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110213312021 is a prime.

Together with 110213312023, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110213312023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55106656010 + 55106656011.

It is an arithmetic number, because the mean of its divisors is an integer number (55106656011).

Almost surely, 2110213312021 is an apocalyptic number.

It is an amenable number.

110213312021 is a deficient number, since it is larger than the sum of its proper divisors (1).

110213312021 is an equidigital number, since it uses as much as digits as its factorization.

110213312021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 110213312021 its reverse (120213312011), we get a palindrome (230426624032).

The spelling of 110213312021 in words is "one hundred ten billion, two hundred thirteen million, three hundred twelve thousand, twenty-one".