110214301320133 has 2 divisors, whose sum is σ = 110214301320134. Its totient is φ = 110214301320132.

The previous prime is 110214301320113. The next prime is 110214301320157. The reversal of 110214301320133 is 331023103412011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 95258810243844 + 14955491076289 = 9760062^2 + 3867233^2 .

It is a cyclic number.

It is not a de Polignac number, because 110214301320133 - 2³⁷ = 110076862366661 is a prime.

It is a super-2 number, since 2×110214301320133² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110214301320098 and 110214301320107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110214301320113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55107150660066 + 55107150660067.

It is an arithmetic number, because the mean of its divisors is an integer number (55107150660067).

Almost surely, 2^{110214301320133} is an apocalyptic number.

It is an amenable number.

110214301320133 is a deficient number, since it is larger than the sum of its proper divisors (1).

110214301320133 is an equidigital number, since it uses as much as digits as its factorization.

110214301320133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 110214301320133 its reverse (331023103412011), we get a palindrome (441237404732144).

The spelling of 110214301320133 in words is "one hundred ten trillion, two hundred fourteen billion, three hundred one million, three hundred twenty thousand, one hundred thirty-three".