Base | Representation |
---|---|
bin | 1010000001100010000100… |
… | …1000101001010000100101 |
3 | 1110000122021020112220221111 |
4 | 2200120201020221100211 |
5 | 2421033403122331223 |
6 | 35235102555545021 |
7 | 2215162415142544 |
oct | 240304110512045 |
9 | 43018236486844 |
10 | 11021441995813 |
11 | 356a192750807 |
12 | 12a004275b171 |
13 | 61c418792542 |
14 | 2a162518215b |
15 | 141a5dd1330d |
hex | a0621229425 |
11021441995813 has 2 divisors, whose sum is σ = 11021441995814. Its totient is φ = 11021441995812.
The previous prime is 11021441995771. The next prime is 11021441995829. The reversal of 11021441995813 is 31859914412011.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9780174164929 + 1241267830884 = 3127327^2 + 1114122^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11021441995813 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11021441995013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5510720997906 + 5510720997907.
It is an arithmetic number, because the mean of its divisors is an integer number (5510720997907).
Almost surely, 211021441995813 is an apocalyptic number.
It is an amenable number.
11021441995813 is a deficient number, since it is larger than the sum of its proper divisors (1).
11021441995813 is an equidigital number, since it uses as much as digits as its factorization.
11021441995813 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 311040, while the sum is 49.
The spelling of 11021441995813 in words is "eleven trillion, twenty-one billion, four hundred forty-one million, nine hundred ninety-five thousand, eight hundred thirteen".
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