Search a number
-
+
110221120212020 = 2255511056010601
BaseRepresentation
bin11001000011111011011010…
…101101111000110000110100
3112110021000222101020101212022
4121003323122231320300310
5103421330323233241040
61030230514505212312
732134133052354656
oct3103733255706064
9473230871211768
10110221120212020
11321355729a0274
1210441712191098
134966a650a49bc
141d30a32dc86d6
15cb2186e2c6b5
hex643edab78c34

110221120212020 has 12 divisors (see below), whose sum is σ = 231464352445284. Its totient is φ = 44088448084800.

The previous prime is 110221120211981. The next prime is 110221120212031. The reversal of 110221120212020 is 20212021122011.

110221120212020 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 2 ways, for example, as 45768932295076 + 64452187916944 = 6765274^2 + 8028212^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 110221120212020.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2755528005281 + ... + 2755528005320.

It is an arithmetic number, because the mean of its divisors is an integer number (19288696037107).

Almost surely, 2110221120212020 is an apocalyptic number.

110221120212020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

110221120212020 is an abundant number, since it is smaller than the sum of its proper divisors (121243232233264).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

110221120212020 is a wasteful number, since it uses less digits than its factorization.

110221120212020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5511056010610 (or 5511056010608 counting only the distinct ones).

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 110221120212020 its reverse (20212021122011), we get a palindrome (130433141334031).

Subtracting from 110221120212020 its reverse (20212021122011), we obtain a palindrome (90009099090009).

The spelling of 110221120212020 in words is "one hundred ten trillion, two hundred twenty-one billion, one hundred twenty million, two hundred twelve thousand, twenty".

Divisors: 1 2 4 5 10 20 5511056010601 11022112021202 22044224042404 27555280053005 55110560106010 110221120212020