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11022212200271 is a prime number
BaseRepresentation
bin1010000001100100111100…
…0010101111011101001111
31110000201020220211100211112
42200121033002233131033
52421041442310402041
635235311232042235
72215220456601566
oct240311702573517
943021226740745
1011022212200271
11356a548490818
1212a021869337b
1361c50c21251c
142a1699592bdd
15141aa6751deb
hexa064f0af74f

11022212200271 has 2 divisors, whose sum is σ = 11022212200272. Its totient is φ = 11022212200270.

The previous prime is 11022212200217. The next prime is 11022212200273. The reversal of 11022212200271 is 17200221222011.

Together with previous prime (11022212200217) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11022212200271 - 226 = 11022145091407 is a prime.

Together with 11022212200273, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11022212200273) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5511106100135 + 5511106100136.

It is an arithmetic number, because the mean of its divisors is an integer number (5511106100136).

Almost surely, 211022212200271 is an apocalyptic number.

11022212200271 is a deficient number, since it is larger than the sum of its proper divisors (1).

11022212200271 is an equidigital number, since it uses as much as digits as its factorization.

11022212200271 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 448, while the sum is 23.

Adding to 11022212200271 its reverse (17200221222011), we get a palindrome (28222433422282).

The spelling of 11022212200271 in words is "eleven trillion, twenty-two billion, two hundred twelve million, two hundred thousand, two hundred seventy-one".