Base | Representation |
---|---|
bin | 10100100001111110… |
… | …10101000000011101 |
3 | 1001110011200201110011 |
4 | 22100333111000131 |
5 | 140033222023223 |
6 | 5021425243221 |
7 | 540101214526 |
oct | 122077250035 |
9 | 31404621404 |
10 | 11022454813 |
11 | 4746985497 |
12 | 2177493511 |
13 | 106878a216 |
14 | 767c7784d |
15 | 447a2780d |
hex | 290fd501d |
11022454813 has 2 divisors, whose sum is σ = 11022454814. Its totient is φ = 11022454812.
The previous prime is 11022454811. The next prime is 11022454831. The reversal of 11022454813 is 31845422011.
Together with next prime (11022454831) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10871607289 + 150847524 = 104267^2 + 12282^2 .
It is a cyclic number.
It is not a de Polignac number, because 11022454813 - 21 = 11022454811 is a prime.
Together with 11022454811, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11022454811) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5511227406 + 5511227407.
It is an arithmetic number, because the mean of its divisors is an integer number (5511227407).
Almost surely, 211022454813 is an apocalyptic number.
It is an amenable number.
11022454813 is a deficient number, since it is larger than the sum of its proper divisors (1).
11022454813 is an equidigital number, since it uses as much as digits as its factorization.
11022454813 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7680, while the sum is 31.
Adding to 11022454813 its reverse (31845422011), we get a palindrome (42867876824).
The spelling of 11022454813 in words is "eleven billion, twenty-two million, four hundred fifty-four thousand, eight hundred thirteen".
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