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1102301322181 is a prime number
BaseRepresentation
bin10000000010100110010…
…001110101101111000101
310220101020021102001021121
4100002212101311233011
5121030003114302211
62202220142513541
7142432024433443
oct20024621655705
93811207361247
101102301322181
113955353a5454
121597725958b1
137cc3c7c4187
143b4ccd9bb93
151da17a34271
hex100a6475bc5

1102301322181 has 2 divisors, whose sum is σ = 1102301322182. Its totient is φ = 1102301322180.

The previous prime is 1102301322173. The next prime is 1102301322193. The reversal of 1102301322181 is 1812231032011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 652072400100 + 450228922081 = 807510^2 + 670991^2 .

It is a cyclic number.

It is not a de Polignac number, because 1102301322181 - 23 = 1102301322173 is a prime.

It is a super-2 number, since 2×11023013221812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1102301322481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551150661090 + 551150661091.

It is an arithmetic number, because the mean of its divisors is an integer number (551150661091).

Almost surely, 21102301322181 is an apocalyptic number.

It is an amenable number.

1102301322181 is a deficient number, since it is larger than the sum of its proper divisors (1).

1102301322181 is an equidigital number, since it uses as much as digits as its factorization.

1102301322181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 1102301322181 its reverse (1812231032011), we get a palindrome (2914532354192).

The spelling of 1102301322181 in words is "one trillion, one hundred two billion, three hundred one million, three hundred twenty-two thousand, one hundred eighty-one".