Base | Representation |
---|---|
bin | 10000000010100111011… |
… | …101101011011111011111 |
3 | 10220101021122211002212102 |
4 | 100002213131223133133 |
5 | 121030023212000132 |
6 | 2202222132555315 |
7 | 142432355425502 |
oct | 20024735533737 |
9 | 3811248732772 |
10 | 1102321203167 |
11 | 395545644318 |
12 | 159779182b3b |
13 | 7cc43965382 |
14 | 3b4d1895139 |
15 | 1da1965ec62 |
hex | 100a776b7df |
1102321203167 has 2 divisors, whose sum is σ = 1102321203168. Its totient is φ = 1102321203166.
The previous prime is 1102321203161. The next prime is 1102321203169. The reversal of 1102321203167 is 7613021232011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1102321203167 - 26 = 1102321203103 is a prime.
It is a super-2 number, since 2×11023212031672 (a number of 25 digits) contains 22 as substring.
Together with 1102321203169, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1102321203161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551160601583 + 551160601584.
It is an arithmetic number, because the mean of its divisors is an integer number (551160601584).
Almost surely, 21102321203167 is an apocalyptic number.
1102321203167 is a deficient number, since it is larger than the sum of its proper divisors (1).
1102321203167 is an equidigital number, since it uses as much as digits as its factorization.
1102321203167 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 29.
Adding to 1102321203167 its reverse (7613021232011), we get a palindrome (8715342435178).
The spelling of 1102321203167 in words is "one trillion, one hundred two billion, three hundred twenty-one million, two hundred three thousand, one hundred sixty-seven".
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