110233154111081 has 2 divisors, whose sum is σ = 110233154111082. Its totient is φ = 110233154111080.

The previous prime is 110233154110991. The next prime is 110233154111083. The reversal of 110233154111081 is 180111451332011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 98207406301225 + 12025747809856 = 9909965^2 + 3467816^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-110233154111081 is a prime.

It is a super-3 number, since 3×110233154111081³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 110233154111083, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (110233154111083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55116577055540 + 55116577055541.

It is an arithmetic number, because the mean of its divisors is an integer number (55116577055541).

Almost surely, 2^{110233154111081} is an apocalyptic number.

It is an amenable number.

110233154111081 is a deficient number, since it is larger than the sum of its proper divisors (1).

110233154111081 is an equidigital number, since it uses as much as digits as its factorization.

110233154111081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 32.

The spelling of 110233154111081 in words is "one hundred ten trillion, two hundred thirty-three billion, one hundred fifty-four million, one hundred eleven thousand, eighty-one".