Base | Representation |
---|---|
bin | 10100100010001100… |
… | …00010011111111011 |
3 | 1001110022000002121122 |
4 | 22101012002133323 |
5 | 140034144322021 |
6 | 5021531055455 |
7 | 540122162426 |
oct | 122106023773 |
9 | 31408002548 |
10 | 11024214011 |
11 | 4747977178 |
12 | 2177ba158b |
13 | 1068c54b75 |
14 | 7681b49bd |
15 | 447c73bab |
hex | 2911827fb |
11024214011 has 2 divisors, whose sum is σ = 11024214012. Its totient is φ = 11024214010.
The previous prime is 11024213999. The next prime is 11024214013. The reversal of 11024214011 is 11041242011.
11024214011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11024214011 - 222 = 11020019707 is a prime.
Together with 11024214013, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (11024214013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5512107005 + 5512107006.
It is an arithmetic number, because the mean of its divisors is an integer number (5512107006).
Almost surely, 211024214011 is an apocalyptic number.
11024214011 is a deficient number, since it is larger than the sum of its proper divisors (1).
11024214011 is an equidigital number, since it uses as much as digits as its factorization.
11024214011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 11024214011 its reverse (11041242011), we get a palindrome (22065456022).
The spelling of 11024214011 in words is "eleven billion, twenty-four million, two hundred fourteen thousand, eleven".
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