1102440221 has 2 divisors, whose sum is σ = 1102440222. Its totient is φ = 1102440220.

The previous prime is 1102440203. The next prime is 1102440223. The reversal of 1102440221 is 1220442011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 829728025 + 272712196 = 28805^2 + 16514^2 .

It is an emirp because it is prime and its reverse (1220442011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1102440221 is a prime.

Together with 1102440223, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1102440221.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1102440223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551220110 + 551220111.

It is an arithmetic number, because the mean of its divisors is an integer number (551220111).

Almost surely, 2^1102440221 is an apocalyptic number.

It is an amenable number.

1102440221 is a deficient number, since it is larger than the sum of its proper divisors (1).

1102440221 is an equidigital number, since it uses as much as digits as its factorization.

1102440221 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 128, while the sum is 17.

The square root of 1102440221 is about 33203.0152395833. The cubic root of 1102440221 is about 1033.0428824903.

Adding to 1102440221 its reverse (1220442011), we get a palindrome (2322882232).

The spelling of 1102440221 in words is "one billion, one hundred two million, four hundred forty thousand, two hundred twenty-one".